1. E at pt P is 8.99* 6 NC*-1to the left.
Force on Q3 is 27 N to the left.
Work done in bringing Q3 is 1.08 J (negative sign as work is done by field itself)
2. E at fourth corner = 1.08x10*7 NC*-1 at 25.5 degrees to the horizontal.
Force on Q at P = 21.6 N at 25.5 degrees to the horizontal.
Potential at O = 1.02 x 10*6 NC*-1
3. v = 4.87x10*7 ms*-1
v= 6.89x10*7 ms*-1
4. E = 1x10*4 NC*-1
a = 1.76x10*15 ms*-2
time= 1.43x10*-9 s
v= 7.004x10*7 ms*-1
