Self attempt
Question 9
KE1 + PE1 = KE2 +PE2
0 + mgh = 0.5 mv2 + 0
gh = 0.5 v2...........1
gh' = 0.5 (2v)2..............2
divide 1 by 2
h'= 4h
Question 10
a) Total ME = mgh = 147J
b) KE = 147J
v = 31.3 ms*-1
c)PE = mg(10)
ME = PE +KE
147 = mg(10) + KE
KE = 117.6 J
Ratio of KE/PE = 117.6/mg(10) = 4