Points to ponder:

1. The proving question requires two equation to be written separately and deriving Irms in terms of I .

2. When the V is increased , I is reduced, hence power loss is reduced. percentage power transmitted is higher.

3. When the V is lowered, I is increased, hence power loss is increased , % is increased. The peak voltage can be found by multiplying the rms voltage by 1.414. Rms voltage gives rms current , if multiply by 1.414 gives peak current.

4 A half rectified circuit , gives half the waveform , the other direction get truncated. The peak power is Vo2/R gives 477 J,