1a No external force acting on the system
b The force is opposite and hence the gradient is positive and negative
ii) The initial momentum is equal to final momentum = 36KNs
iii) The force is change in momentum divide by time taken F= 2.7 kN
iv) The KE is not conserved as intial is 11.4 kJ and final is 10.8kJ. Hence change of 6kJ. The collision is inelastic.
3a Force multiply by perpendicular distance
b) The three forces are Wbricks , W beam and Rx and Ry at the hinge.
ii) The tension increases as the W bricks is moved towards the end P as the moment increase. To remain balance T must remain the same
iii) the Tension = 2880N
4 Energy level is the energy state an electron can occupy
b) A: Emission line spectra
B: line absorption spectrum.
A :cooler gas excited by the white light will emit photon of specific wavelength
B: White light is absorped by cooler gas has some dark lines missing over bright backgd .
ii) 1 The freq f= 6.2 x 1014Hz 2 E2-E1 = 4.10 x 10-19 - hf = 3.0 x 10-19. f= 4.52 x 1014 and wavelength = 6.65 x10-7m
5. change MeV to Joule
b) Photon E = hf.
c) the loss in ke = 550 (photon energy) divide by energy of proton
d) Use photoelectric equation max KE = hf - work function
e) No of electron = 3 power of 10 = 59049
f) I = Q/t = 550e /time = 4.1 x 10-7
7. ii) R = 3 ohm using P = V2/R
2. length of wire is 9.5 cm
3. I = E/R+r
where R = parallel of 1.5 and 6 ohm .
3 I = 9.8 A
4 When a large current is drawn from the battery , the pd across the battery is E - Ir which is much smaller . Hence the lamps will be less bright as pd across the lamps is reduced.
5. 2 % of 48 W divide by photon energy =
rate of photon emitted .N = 2.7 x 1018 s-1
8 Force is perpendicular to velocity hence the force in the dir of vel is zero . The direction of motion changes but the speed remain constant,
9 qV = 0.5 mv2
v2 = 2eV/m where V = 2.8 kV
v = 3.1 x 107 ms-1
ii) 1 a = QE/m = 3.5 x 1015 ms-2
2. L = v/t, t = 3.87 x10-9 s
3. W = Fs where s = 0.5 at2
W = Fs= 3.2 x 10-15 x 0.5 (3.51 x 1015( x( 3.9 10 -19 ) =0.263 J
4. v = 1.07 x 104 ms-1
5 angle = 23.7 deg.
iii Proton deflect below the horizonal and the velocity and angle of deflection will be smaller than that of electron as the acc is small
