1 ADDCD
6 CCBDB
11 BCDBA
16 DCDBC
21 DADAD
26 BCCBB
31BBCDB
36BDDCC
6. The total momentum = 0 . final vel = 0 . To find the force on each , consider either the 6 kg or the 10 kg alone. The change in p = 30 . The force = 30/0.2s= 150 N
8. Find the centre of mass of the woooden and rubber handle. The ratio of masses
Mw(0.9)= Mr(1.6) using summation of moment. density = mass / vol , hence dr/dw= (mr/mw) ( vw/vr) but v = AL.
The ration dw/dr = (0.9/1.6) ( Lw/Lr) = (0.9/1.6) (4/1) = 2.25
10. The work done depends on opposing force which is dependant upon the induced current. Hence F = BIL where I= E/r = BLv/r. Hence force F is directly proportional to v . Hence workdone is directly proportional to v.
18. gradient of graph = 1/nrT. Hence if amount of gas and temperature is doubled .
grad = 1/4 (nrT) . hence 1/4 of original gradient.
21. K = hc = 1.99 x 10 -25 Jm . converting the unit to eV and nm .
The K = 1.99 x 10-25 J(1 eV/1.6x-19J)=1.24x10-6 eVm= 1.24 x 10-6 eV(109nm/1m)m = 1.24x103 eVnm. Now it is properly converted to eVnm . Note : the conversion to unit that you want involves multiplying by unit . The bracketed ratio = 1
23 If the maximum order is 5 , so the total image is 5 + 5 +1 =11
25. Work done on the charge must be a positive value. Hence q(higher V- lower V) = q (V1-V2) .
29. The pd drop across the thermistor is 3V , the pd drop across the R (at the base is also 3V. Hence the voltmeter is 0V.
The pd drop across thermistor (5R) is now 5V , the pd drop across the R(at the base) is still 3V . Hence the pd across the voltmeter is 2V.
32. Resolve B to the components . Bsin@ is perpendicular to area . Hence flux linkage= BAnsin@. When rotated to zero degrees , flux linkage = 0 . hence the change in flux linkage = BAn sin @
35. If velocity is increased , the de broy wavelength of the electron is decreased. Using dsin@ = n(wavelenth) , the angle @ is smaller , so diameter of circle is decreased.
39. The activity 532 per min must deduct 24 per min and then divide by 4 due to 2 half lives. The final answer add 24 per min.
