Wednesday, October 13, 2010

H2_07_paper2

1.ai) acc=9.715 ms-2
aii)1. 0.376% 2. 0.676%
b)
Use s = 1/2 at2, a = 2s/t2,
% error in a = % error in s + 2(% error in t)= 0.376 + 2(0.676)= 0.017%
g = 9.715 + 0.2 = 9.7 +0.2 ms-2
c) 1 . Reaction time when stopping the stopwatch and starting the stopwatch.
2. The determination of the exact point where the ball reaches the distance h .

2. b) i) direction of electric field X to C
ii) F = qE where E is read off the graph at x = 2 cm
F= 1.6 x 10-19 x (2.4 x 103) = 3.84 x 10-16 N
ci)pd = 96V Use Fd=qV, V = Fd ,q= Ed which is area under the graph= 2.4x103 (4x10-2)
ii) This pd is an underestimate as the force at x=2cm is below the average force over 4 cm. Or the actual area is larger than the estimated area , hence an underestimate.

3b) Three conditons for observable interference pattern : 1. the waves must meet. 2. the amplitudes are approx the same 3. the sources are coherent
ii)1. number of directions is 7
2. draw a minimum line in between two maxima line.

4. a) out of page
Bqv = m v2/r
B(2e)r = mv where mv = p
p = 2Ber
ii) Ke = 1/2 mv2=p2/2m
hence Ek = (2Ber)2/2m
= 2(Ber)2/m
c) The speed is greater , the radius of curvature is larger . (straighter)

5. a) electrons from n-type diffuse to the left side the p -type
b) As the electron diffuse to the p-type material at the junction, immobile ions exist in the n and p type create an internal electric field that prevent further diffusion of charges. This region is depleted of mobile charge carrier and hence the formation of depletion region.
c) Positive terminal of battery to the n type material will increase the width of the depletion region. Negative terminal is to the ptype material.

6. a)X is proton
b) Sum (N + He) - Sum of (O+X) = m . Convert m to energy using E = mc2
ii) The reaction can occur if the KE of the reactant is larger than the KE of the product by 1.9x 10-13J.
iii) The oxygen and nucleus X move apart and hence the conservation of momentum is valid as the helium nucleus is moving with high velocity. The KE of the helium nucleus is larger than the KE of the oxygen and X by the difference suggest in ii)